The only place this comes up is in question 23. Answer choice (A) says, "at most 2 of each kind of animal," which applies to all 3 kinds of animals. It is not true that for all 3 kinds of animals, one can have at most 2. For example, we're definitely allowed to have all 3 pandas, or potentially in another hypothetical all 3 raccoons.
I like to frame these Closed Binary Grouping games based on the numerical distributions.
Here we can clearly see we're allowed to have all 3 of one kind of animal, but since we're only choosing 6, there's no way we could have all 3 of each kind of animal all at once!
Answer choice (B) says, "at least 1 of each kind of animal," which applies to all 3 kinds of animals. It is true that for all 3 kinds of animals we are must have at least 1 of each kind. If we were to have 0 of any kind of animal, either N and T would both be selected (assuming 0 monkeys), or F and H would both be selected (assuming either 0 pandas or 0 raccoons).
Hope that helps!