MarieB112 Wrote:Hi!
i see why C does not work but when i test B it does not seem to work for me either... why is B okay?
B is okay because when you put PT in Group 1 that means the only flowers that could go in Group 3 is S and R. (L is not allowed in Group 3 because of the condition rule that says If L then no S but we already have S in Group 3 by the set up).
This in turn then implies Group 3 will have both S and R as that is the only way for the rule on Group 2 and Group 3 to share exactly 2 of the same flowers ( of the 5 flowers 3 flowers can not go in Group3) . This in turn means that Group 2 must have at least both S and R.
This would not violate any rules so that's why B works
I think the key to this question (and game as a whole) was asking who is left after placing what is known on who is in Group 1 or Group 3 because that any placement in either of the two groups affects the other group . And then we also know Group 3 needs at least 2 flowers to satisfy the other rule (the sharing flowers with Group 2 rule)