Q22

[aebq196234]

I had issue with this question. I could not see why 22 could not also be C.

i made three frames one of is completely filled with 1= po 2=Ts 3=NM

and another where F=2 G=1 and 3= H
and the last one i made is F=3 G=1 and H=2

I had made some other inferences for these but i wrecked them trying to solve this problem. but it felt like with one of my hypotheticals i could make C work.

[timmydoeslsat]

I had issue with this question. I could not see why 22 could not also be C.

i made three frames one of is completely filled with 1= po 2=Ts 3=NM

and another where F=2 G=1 and 3= H
and the last one i made is F=3 G=1 and H=2

I had made some other inferences for these but i wrecked them trying to solve this problem. but it felt like with one of my hypotheticals i could make C work.

We know that this is not going to work. How could M be 3rd place yet still be above the H team?

This was a question that did not lead to any up front inferences. We still know that H is either going to second or third. Lets run both hypotheticals with us knowing that M has to be above the H team.



Since I do not know the placements of G and F in the second hypothetical, I will solve the first one and see if the answer is there for the could be true question.



None of the answers are there.

At this point, I would show G1 and then G2.





We quickly see that the G2 scenario would be unacceptable. We would be forced to place M and P together, as neither variable can go at the bottom. (M must come before H due to our local rule, and P must always be above N)

So the G1 scenario is the only one to do.



We know that M and P cannot be on the last team, as discussed above. This means that the bottom two must be O and N. We can dual option the M and P.



So we know that P can be first (E).