by WeihuaJ277 Thu Dec 31, 2020 4:50 am
Hi, Amy.
I think this question can be solved by the exclusive method, especially within the limited time and not quite clearly to the whole game.
It can be easily deduced that those five group as Jackson with timmons, Katz with vega, Lu with yoder, Norales with wilson and Odede with zheng. Then you can quickly eliminate choice B and D. (Norales along with wilson could not be the 4th, and yoder, together with L, should not be the second one for it must later than J and Katz.
While it sill leaves A, C and E, it can be that if choice A would be the right one, which means Jackson is at the third slot, leading Katz must be the fourth one. That's equivalent with C. However, this question only has one correct answer, so must be the choice E.
Alternatively, you can put wilson in the 3rd slot and 5th slot respectively and analyze what could be true, but I think it might be a little time-consuming. When wilson is in the 3rd slot, it's obvious that J could not be the 3rd slot.
It would be like this:
J K N __ __
T V W__ __
When wilson is in the 5th slot, you'll find that J and L could not be the third and the fourth respectively, because there's also a slot needed to L after K.
It would be like this:
O J K L N
Z T V Y W
(jut one example under this option)