Q17

[ShehryarB30]

Could you pls explain this

[ohthatpatrick]

I'll use a setup like this,
F: __ __ ~r
G: __ __
H: __ __ (t, __)
J: __ __ ~y

We'll be putting an R, S, T, and Y into each column.
We have a "y s" chunk that can only go into F or G.

Q17 tells us to put a 't' in J1.

F: _ , _ ~r
G: _ , _
H: _ , _ (t, _ )
J: t, _ ~y

That means the other 't' is in H2.

F: _ , _
G: _ , _
H: _ , t
J: t, _

It looks like the "y s" could still go in F or G, so we better just frame those options.
F: y , s
G: _ , _
H: _ , t
J: t, _

F: _ , _
G: y , s
H: _ , t
J: t, _

We still need two r's, and they can't go in row F.
That's most helpful on the lower frame, which would now have to look like this:
F: _ , _
G: y , s
H: r , t
J: t, r

Who's left?
Another s and y.
F: s , y
G: y , s
H: r , t
J: t, r

We didn't finish off the other frame, because the two r's have multiple options, but let's see if we can get an answer from the one above and the partial scenario we have from the other frame:
F: y , s
G: _ , _
H: _ , t
J: t, _


(A) maybe on this lower frame
(B) maybe on this lower frame
(C) never. eliminate.
(D) nope, on the lower frame, s would be J2, but it's already F2.
(E) never. eliminate.

So we have to try (A) or (B) out on the lower frame. Let's try R at G2 on the lower frame:
F: y , s
G: _ , r
H: _ , t
J: t, _

That forces the other r to be H1.
F: y , s
G: _ , r
H: r , t
J: t, _

Who's left?
We need an s1 and a y2 ... but it would result in this
F: y , s
G: s , r
H: r , t
J: t, y

y can't go into J's row, so apparently (A) can't happen.

Let's pick (B). For what it's worth, it would have looked like this:
F: y , s
G: r , y
H: s , t
J: t, r