by ohthatpatrick Wed Apr 18, 2018 2:09 am
It's been a long time since I've played this, but I remember it being a hard game, so it's possible there's no good answer, and this is just a tough question.
I would react to the condition that "same type can't be adjacent" by initially not caring about F G Q R S V W and only thinking about p's, L's, and i's. (professors, lecturers, instructors)
If the three L's have to be split up, that already claims 5 spaces (two things needed to buffer the three L's apart from each other).
We'll be buffering the L's with either i's or p's.
L - i/p - L - i/p - L
Because rule 1 precludes us from ever having i's and p's next to each other, we also need these L's to buffer the remaining two i/p's from each other.
So we're essentially stuck with
i/p - L - i/p - L - i/p - L - i/p
That's the only way to keep members of the same rank away from each other.
But there's more! Given rule 2, that p's can't be on either bookend, it actually has to go
i - L - p - L - p - L - i
I would go to the answers at this point, since knowing the order of rank has to be
i - L - p - L - p - L - i
should help us interpret the answers.
(A) F is a p, so F would be in 103 or 105.
(B) Q is an L, so Q would be in 102, 104, or 106
(C) R is an L, so R would be in 102, 104, or 106
(D) S is an L, so S would be in 102, 104, or 106
(E) Yes. V is an i, so V would be in 101 or 107
TAKEAWAY: since the "if" condition they give us isn't about specific characters, instead it's about the 2nd layer info about their job rank, you want to focus your thinking only on what this means for the arrangement of professors, lecturers, and instructors.