Q13

 
megm7267
Thanks Received: 0
Jackie Chiles
Jackie Chiles
 
Posts: 36
Joined: November 07th, 2010
 
 
 

Q13

by megm7267 Sun Apr 10, 2011 2:43 pm

For this question it seems like there are several that could be true, however I don't find the answer that must be true.

Is this a trial and error question?

Thanks
User avatar
 
bbirdwell
Thanks Received: 864
Atticus Finch
Atticus Finch
 
Posts: 803
Joined: April 16th, 2009
 
 
 

Re: Q13

by bbirdwell Thu Apr 14, 2011 9:03 pm

Make inferences!

Given the constraint from this problem (1 skirt = 2 jacket), there's only two possibilities: 1's skirt can be red (and therefore 2's jacket), or 1's skirt can be yellow (and therefore 2's jacket). 1's skirt cannot be navy because 2 always has the navy skirt.

My diagram for the problem might look something like this:
1 2
H
J r/y
S r/y n
T r x

Then I wonder, "what else do I know?" And since I know all three colors can't go with one mannequin, my attention is immediately brought to 2's hat. Hmmm.... Can't be r because then an r for the jacket would violate the "hat/jacket" rule and a y for the jacket would violate the "all three colors" rule.... Can't be y for the same reasons. Therefore it must be n!

See what I mean?
I host free online workshop/Q&A sessions called Zen and the Art of LSAT. You can find upcoming dates here: http://www.manhattanlsat.com/zen-and-the-art.cfm