by ohthatpatrick Fri Feb 15, 2019 2:48 am
if there are more in group 1 than in group 3, it has to be
__ __ __ __ | __ | __ __
From there I would think that PQ and SU can't go in group 2.
So the T/U choice in group 2 will have to be T.
__ __ __ __ | T | __ __
That means it's P, and thus PQ in group 1.
P Q __ __ | T | __ __
That leaves SU to go in either group 1 or group 3, and KM will go wherever they aren't.
P Q __ __ | T | __ __
...........( SU , KM )
(A) only T in 2
(B) only T in 2
(C) P is in 1
(D) T is in 2
(E) Sure, that'll work.