Thanks for posting
Carlystern!
This is a challenging
Conditional Grouping game, and it's made more challenging by the fact that it has a contraint on the size of the team - at least four must be on the team! We need to set up a logic chain to sort out all this conditional information.
Check out the set up!
![Image](http://i.imgur.com/YalUpK6.png)
This contains all of the rules we have in the game in one place.
The next thing we should notice is that this is a conditional question - great! So we know that Y is in the OUT group. We also know that Y being out will trigger W being out. Nothing else gets triggered yet. We have W and Y in the OUT group, and nothing else is known.
Now, the question says that all of the following could be on the team EXCEPT someone - so 4 of the answers are perfectly fine, and one of the answers is a
rule violator. How are we going to find our rule violator? Y and W being out don't trigger anyone else, so there's no direct rule violation from the chain.
But wait! We have to have at least 4 people on the team. And that means we can't have any MORE than 4 people in the OUT group. (If we did, the team would be too small.) And we already have 2 people out (Y and W). So, if there's an employee who kicks a bunch of people OUT, then that could break the
numerical rules!
M kicks a ton of people out! Let's follow the chain if M is included on the team:
![Image](http://i.imgur.com/3yRg2dl.png)
Ouch!
M kicks out three people. Adding that to our original Y and W would mean that we'd have five people in the out group. We can't have that, as our team would be smaller than 4!
M cannot possibly be on the team in this hypothetical, so
(E) must be the answer.
A quick comment on the other answers:
(A) Z is a free agent. He can always be included!
(B) T being included doesn't trigger anything. Seems fine!
(C) P being included would kick out M, but that's ok - OUT group would have (M, Y, W), and that's not too many.
(D) O being included would also kick M out, and just like in (C), that's ok - OUT group would have (M, Y, W), and that's not too many.
Does that help clear this question up a bit?