Q23

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ManhattanPrepLSAT1
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Q23

by ManhattanPrepLSAT1 Thu Sep 08, 2016 2:44 am

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MarieB112
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Re: Q23

by MarieB112 Sun Oct 29, 2017 7:04 pm

Hi!

i see why C does not work but when i test B it does not seem to work for me either... why is B okay?
 
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Re: Q23

by andrewgong01 Sun Nov 05, 2017 3:49 am

MarieB112 Wrote:Hi!

i see why C does not work but when i test B it does not seem to work for me either... why is B okay?



B is okay because when you put PT in Group 1 that means the only flowers that could go in Group 3 is S and R. (L is not allowed in Group 3 because of the condition rule that says If L then no S but we already have S in Group 3 by the set up).

This in turn then implies Group 3 will have both S and R as that is the only way for the rule on Group 2 and Group 3 to share exactly 2 of the same flowers ( of the 5 flowers 3 flowers can not go in Group3) . This in turn means that Group 2 must have at least both S and R.

This would not violate any rules so that's why B works

I think the key to this question (and game as a whole) was asking who is left after placing what is known on who is in Group 1 or Group 3 because that any placement in either of the two groups affects the other group . And then we also know Group 3 needs at least 2 flowers to satisfy the other rule (the sharing flowers with Group 2 rule)
 
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Re: Q23

by CatherineC439 Sun Sep 27, 2020 9:22 pm

Hello -- Why can L not go in bouquet 1?
 
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Re: Q23

by Laura Damone Thu Oct 29, 2020 5:04 pm

Hi! Please forgive the delay here - technical difficulties swallowed your post!

L can't go in bouquet 1 in the diagram shown for this question ONLY because that diagram is a hypothetical to test answer choice C.

If L, P and R are the only members of Group 2, and Group 2 has to have 2 members in common with group 3, group 3 has to have P and R, since it can't have L.

This means group 1 can't have P or R. The contrapositive of rule 4 tells us that if you don't have R you don't have L. Hence L is crossed off beneath slot 1. The contrapositive of rule 5 tells that if you don't have P you don't have T, which is why T is crossed off beneath slot 1. That leaves nobody to occupy slot 1, violating the numeric requirement that each bouquet has at least one type of flower.

Hope this helps!
Laura Damone
LSAT Content & Curriculum Lead | Manhattan Prep