Diagram

[Hwilliamsvi]

I figured out the answers to questions 1-4, but for question 5

Can anyone give me an idea why it is E instead of D?

[bbirdwell]

The answer is not (D) because F could be paired with J and M in the level 2 class. This leaves room in the level 1 class for I, G, and K in level 1, and L, H, and N in level 3.

(E) is correct because if F, L, and M were all together, they'd have to be in level 2. That leaves I, G, J, and K to go in level 1, which isn't possible because there are only three spaces in each class.

Does that clear things up? Let me know if you want me to get more detailed, show you my setup, etc.

[nazu.s.shaikh]

I'm having a bit of trouble with this game. I'm wondering if it is because of my diagram, did I do it incorrectly?

I > G > J & K

And from J & K I have to separate branches from them.

J > M > H > N

K > F
---
L

Also for Q#3, how is it that Kathy can be placed in any class if she has two others below her (F/L) If Kathy was to be placed in C3 then F&L would have to be there as well? Doesn't that go against the constraints?

Q5 does not makes sense to me because Kathy scored higher than F&L .. she should not be in the same class as F&L... how is C not correct? Am I misinterpreting the rules here? and regarding your explanation of D... J can't go with M because J scored higher than M how can they be in the same class?

[ManhattanPrepLSAT2]

Your diagram seems right on --

Once again, I think the issue you've run into has to do with understanding the scenario correctly. Nine students take the test and get 9 scores -- it does not mean that everyone in the level 1 scored exactly the same, everyone in level 2 scored exactly the same, etc.

To illustrate -- let's imagine we have 9 people and they all get different scores on a test that is scored 1- 10, 10 being best.

Person A gets a 1
B gets a 2
C = 3
D = 4
E = 5
F = 6
G = 7
H = 8
I = 9

I, H and G would go in class 1
D, E and F would go in class 2
A, B and C would go in class 3

(BTW, in my simple example, no one got the exact same score, but they certainly could have and it would work out just fine).

So, in terms of Q #3, even though 2 people (F and L) score lower than Kathy, she can still be in the lowest class.

In that case, F, L and K would comprise the level 3 class.

I believe you were confused about #5 because of the same issue. Hopefully the explanation above clears it up for you. Please let us know if you have any follow up questions.

[ManhattanPrepLSAT1]

Hi,

Question 3 is giving me real problems. I have sketched the tree with little trouble yet actually deducting who comes within which class is proving difficult. Please help. Is there a solution pdf?

Thanks

Happy to help. For question three we are looking for a student who could be placed in all three classes. Consult the setup I've attached first.



You should see that I and G must be assigned to class 1. They're out. J or K are the only other students who could be assigned to class 1. One of them must be the correct answer. However, we can eliminate J, since J cannot be assigned to the third class. This is because M, H, and N must all be assigned to lower classes than J, so there is no room for J in class 3.

That leaves K as the only student who could be placed in all three classes.

[mlbrandow]

I figured out the answers to questions 1-4, but for question 5

Can anyone give me an idea why it is E instead of D?

Figure 1.0 shows a default setup which intuitively prohibits FLM due to the four letters that must precede for group 1.

Figure 1.1 shows a situation where FJM can be together in group 2.

[ManhattanPrepLSAT1]

Nice setup mlbrandow!