Diagram

[case0403]

I am having a hard time with the set up. But really the last couple of constraints. Can someone explain to me how the set up should look. Thanks

[ManhattanPrepLSAT1]

Happy to help out with the setup for this game (see attached). I think you'll be disappointed with the constraints as they're not as complicated as you might have thought originally.

Let me know if you need help with some of the questions.

[cyruswhittaker]

In reference to the last two rules, notice that they set up biconditionality:

~U--->R2

R2---->~U

Thus, R2 is a condition that is both necessary and sufficient for ~U.

As a result, U is in the race and R does not run second or U is out of the race and R runs second. With this, two different templates can be constructed.

When U is out of the race, the five into four numerical restriction leads to a single unique solution:

S, R, Q, T

When U is in the race, notice that R can not be placed in slot 2 so indicate this on your diagram.

[monicaiannacone]

Hi, I had the same setup for this game but it took me 10 minutes and I got 3/6 correct, I missed #13, 15, 16. Each of these are MBT or MBF questions. Are there inferences that can be made to make these easier/quicker to solve (aside from creating all those frames)?

Also, I was thrown a little by the conditional aspects of this game and the language about "the coach's selection" which almost made me think it was open binary (and almost made me use a logic chain). i did use the correct setup but wasted some time thinking about the logic chain- is this a hybrid or how can I have noticed how to set it up correctly right away?

If Q -> QT
If ~U<->R2

Thanks!

[timmydoeslsat]

It is technically both a binary and ordering game. We have an in-out dynamic and we must order the variables from 1-4.

It is so important to note that we are selecting 4 of 5. Once we determine one person who is out, the rest of the group must all be in.

Consider this equivalent situation:
_________________________________________________

Two people will be selected to a committee out of a roster of three people: A, B, and C.

The following rules must be followed:

If A is selected then B must be selected.
_________________________________________________

Notice what happens if B is not selected.

That would mean A is not selected.

That would have two people "out" when we can only have 1.

Big picture: When you have a situation of selecting all items but one, and you have a conditional relationship such as A--->B.....you know for a fact that B must be present. This is because its absence would present 2 variables being out.


For this game, we know that T must be in. If T were not in, then Q would not be in. That is not possible as we can only have 1 person out.

Also, I did not find this game to be frame-friendly. I always, as should you, have thoughts about framing. I considered having Q out frame and Q in frame. But there are simply too many possibilities and not many inferences. Same with Q in frame, where you could slide the QT block across the 1-4 board, but even that idea is not limited that much as to who has to be out.