Under probability, there was an example given, i.e. what is the probability of rolling three dice, and getting at least one six?
MGMAT's strategy is to calculate the probability of not getting a 6 (i.e. 5/6 x 5/6 x 5/6 = 125/216) and reducing 1 from this figure to get the answer. (The answer is 91/216)
However, I calculated it as follows:
(probability of getting one six) + (probability of getting 2 sixes) + (probability of getting 3 sixes)
= 3(1/6*5/6*5/6) + 3(1/6*1/6*5/6) + 3(1/6*1/6*1/6)
= 93/216
I multiplied each probability by 3 in order to take into account the separate scenarios of dice 1, dice 2 or dice 3 rolling a 6 individually.
I understand the logic of MGMAT's approach but I'm uncertain as to why my approach doesn't seem to work. Hope you can help clarify this. Thanks!