a couple of notes.
one:
Saurav Wrote:A. 4 is the integer that is closest to x+y
3.5 < X + Y <= 4.5 ( I have taken <= with 4.5 since I observed GMAT rounds down 0.5, contrary to mathematics)
no, the gmat doesn't round 5's down in general. and neither does anyone else.
the biggest thing to notice here is that the issue of "rounding" isn't even a factor in this problem.
in fact,
the problem goes out of its way to avoid using the term "rounding", because the issue of how to round EXACT 5's (i.e., 5's that are not followed by anything else, except maybe a bunch of zeroes) is actually a source of some disagreement in the mathematical, scientific, and even banking community.
specifically, "traditional" rounding rounds ALL 5's
up, ALL the time, even if they're followed by nothing at all.
there's another method of rounding, though, called "convergent rounding" or "bankers' rounding" (read about it
here). this method rounds 5's up if they're followed by any nonzero digits - just as does traditional rounding - but it rounds
exact 5's (not followed by any other digits) to the nearest
even number.
you may never have heard of this second method, but it's in wide use, especially in the scientific community.
this is why the problem doesn't contain the word "round": according to traditional rounding, 4.5 rounds to 5, but according to bankers' rounding, 4.5 rounds to 4. that's bad.
the wording in the actual problem, though, is completely unambiguous: "4 is
the integer that is closest to x + y".
this statement actually rules out BOTH 3.5 and 4.5, because each of those numbers is
equidistant from two integers: the former from 3 and 4, and the latter from 4 and 5.
therefore, here are the CORRECT rephrases:
(1)
3.5 < x + y < 4.5
(2)
0.5 < x - y < 1.5
all four of those signs are strict inequalities. there are no
<'s or
>'s in this problem.
--
two:
there's no reason to separate the "sandwich inequalities" into two inequalities apiece; if you do so, you're merely doing twice the work in order to achieve the same result. not a good thing in general, but especially not on a time-management-intensive test.
you can add all 3 corresponding parts of the inequalities directly:
3.5 < x + y < 4.5
0.5 < x - y < 1.5
_____________________
4 < 2x < 6
therefore
2 < x < 3
notice that all this discussion of <'s,
<'s, >'s, and
>'s is immaterial in the final analysis, because there are still numbers greater than 2.5 (which are closest to 3) and numbers less than 2.5 (which are closest to 2). therefore, insufficient even if you misinterpret the question prompt as referring to "rounding".
but they
could, easily, write a problem that would turn on the inclusion/exclusion of a number such as 4.5. i could write such a problem easily by making minor modifications to this problem (i can do so if any posters here would like to see such a problem).