by GMAT 2007 Thu Aug 23, 2007 1:08 am
[editor: this post was corrected on 23/jul/2008 -- there were some faulty numbers in it]
The problem deals with the Standard deviation in the distribution. By definition we know the standard deviation is the measure of how spread out the distribution is. Also it is given the distribution is symmetric about the mean m. It means the elements are evenly disributed around the mean.
[editor: actually, you don't need to know anything at all about the meaning of standard deviation to solve this problem; the symmetry of the distribution is the only salient fact. see my post below, dated 23/jul/08. --ron]
For ex - in distribution 2,4,6,8,10 - elements (2,4) & (8,10)are symmetric about the mean 6.
Now, we need to find the percent of the distribution greater then (m+d)
Statement (1) -
68% of the distribution lies between (m-d) & (m+d). Since the distribution is symmetric, Hence
The percentage distribution between (m-d) & m = 34%
The percentage distribution between m & (m+d) = 34%
Also,
The percentage distribution less than (m-d) will be 16% and
The percentage distribution greater than (m+d) will be 16%, Sufficient.
Statement (2) -
The percentage distribution less than (m-d) = 16%. From the question we know the distribution is symmetric, so 50% of the distribution should be less than m and 50% of the distribution should be greater than m.
Since, the percentage distribution less than (m-d) = 16%
So the percentage distribution between (m-d) & m = 34%
and the percentage distribution between m & (m+d) will be 34% too and
Percentage distribution greater than (m+d) will be 16%
It is sufficient too.
GMAT 2007