Simplify: (4^y+4^y+4^y)(3^y+3^y+3^y)

[griffin.811]

5th ed. Algebra Guide p.45 Q.7

I can simplify this expression to:
(4*4^y)(3*3^y)

but can someone explain how I get from the above, to:
(4^y+1)(3^y+1)

Thanks

[RonPurewal]

4 is the same as 4^1. Then just use normal exponent rules.

If you still don't see how it works, try it for a couple of specific values of y.

[griffin.811]

Thanks, makes sense.

[RonPurewal]

You're welcome.