by blue_lotus Fri Aug 29, 2008 10:54 am
In work problems the total part of work to be completed is always 1
Let A take 'a' hours to fill the tank alone .
-Means it takes 'a' hours to complete the total part (1).
-This also means A does 1/a part of the work per hour.
Let B take b hours to fill the tank alone
Let C take c hours to fill the tank alone
A and B can fill the tank in 6/5 hours to fill the tank
Therefore in one hour they can fill 5/6 part of the tank or say 5/6 part of the work
1/a + 1/b = 5/6 ---------(1)
A and C can fill the tank in 3/2 hours to fill the tank
Therefore in one hour they can fill 2/3 of the tank .
1/a + 1/c = 2/3 ---------(2)
B and C can fill the tank in 2 hours to fill the tank
Therefore in one hour they can fill 1/2 of the tank .
1/b + 1/c = 1/2 ---------(3)
Adding equations 1 ,2 and 3 we get
2[1/a + 1/b + 1/c] = 5/6 + 2/3 + 1/2 = 2
[1/a + 1/b + 1/c] = 1
This means in one hour A , B and C can complete 1 part of the job
Therefore the total time taken by all the three of them = 1 /( work done by 2 in one hour) = 1/1 =1