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bhuwan
 
 

Orange OG - page 62 - DS-D44

by bhuwan Sun Oct 12, 2008 6:08 pm

If n and m are (+) integers, how can the ans choice for statement (2) assume square rt of M = 1/4 (isn't that saying m = 1/4, which is NOT an integer?)
JAnderson
 
 

Orange OG - page 62 - DS-D44

by JAnderson Mon Oct 13, 2008 6:47 pm

The problem states: [deleted by moderator]

Then the book says: [deleted by moderator]

I too was thrown by this because you are right, is says m is a positive integer and 1/4 is not a positive integer.
But I set the problem up in excel to test more positive integer combinations.
If sqrt-/n is an integer, then n must equal 4, 9, 16, 25...
a positive integer raised to a positive integer would yield an integer but the original problem is asking for (sqrt-/m)^n. Test m=5 & n=9 => 1397.54. So while their example is incorrect, it holds that the base equation srqt-/5 must be a positive integer for (sqrt-/m)^n to be an integer.
esledge
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by esledge Wed Oct 22, 2008 6:14 pm

Sorry, but I had to delete the text of the OG problem, as we cannot discuss OG questions. In the future, you could "generalize" such questions to address the math concept without stepping on the toes of the GMAC, and we'll be happy to help.

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