Hey guys and Stacey
Thanks for the original post on OG #217 by slsu on Mon Sep 17, 2007 10:43 pm (copy and pasted below). However, I still don't understand "the second "winning event" looks at the probability that the student from the senior class (800 students) is the other member of the pair. This results in a P = 1/800." I thought the second winning event is 60/800 [b/c there are 60 pairs, or 120 people to start with].
Can someone explain this to me?
Thanks a lot!
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Question:
[Deleted because this question is from a banned source - see below.]
Answer:
(A)
I looked at this problem as having 2 winning scenarios:
(1) 1 Junior, 1 Senior
(2) 1 Senior, 1 Junior
In (1), the "winning scenario" the first "winning event" looks at the probability that the student from the junior class (1,000 students) is a member of a sibling pair (60 pairs). This results in a P = 60/1,000. Then, the second "winning event" looks at the probability that the student from the senior class (800 students) is the other member of the pair. This results in a P = 1/800. The probability of this "winning scenario" is (60/1,000)*(1/800) = 3/40,000.
My question is how come we don't also look at the 2nd winning scenario (2), since a senior could be picked first, then a junior? Then, the probability of either event chain - (1) or (2) occurring would be the sum of these individual probabilities?