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shrads.jp
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Posts: 11
Joined: Tue Dec 08, 2009 5:43 am
 

Number of variations in Signs

by shrads.jp Thu Dec 17, 2009 1:47 pm

I faced the below sum in GMAT Prep yesterday...pls help as i have my exam this week...
i cudnt understand the language of the sum :-((

For a finite sequence of nonzero numbers , the number of variations in sign is designed as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3 ,2, 5, -4 ,-6?
1) One
2) Two
3) Three
4) Four
5) Five
OA 3
RonPurewal
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Posts: 19744
Joined: Tue Aug 14, 2007 8:23 am
 

Re: Number of variations in Signs

by RonPurewal Sat Jan 09, 2010 5:04 am

shrads.jp Wrote:I faced the below sum in GMAT Prep yesterday...pls help as i have my exam this week...
i cudnt understand the language of the sum :-((

For a finite sequence of nonzero numbers , the number of variations in sign is designed as the number of pairs of consecutive terms of the sequence for which the product of the two consecutive terms is negative. What is the number of variations in sign for the sequence 1, -3 ,2, 5, -4 ,-6?
1) One
2) Two
3) Three
4) Four
5) Five
OA 3


see here:
for-a-finite-sequence-of-non-zero-numbers-the-number-t7396.html

just decode the problem -
the number of pairs of consecutive terms --> two terms that appear next to each other (YOU ARE NOT ALLOWED TO RE-ORDER THE TERMS)
... for which the product of the two consecutive terms is negative --> this happens when THE TWO TERMS HAVE OPPOSITE SIGNS.

but yeah - the primary challenge here definitely lies in understanding what's going on in the first place.