In a sequence of terms in which each term is three times the previous term, what is the fourth term?
(1) The first term is 3.
(2) The second to last term is 3**10.
1- Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
2- Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
3- Both statements TOGETHER are sufficient, but NEITHER one ALONE is sufficient.
4- EACH statement ALONE is sufficient.
5- Statements (1) and (2) TOGETHER are NOT sufficient.
We can write a formula of this sequence: Sn = 3Sn-1
(1) SUFFICIENT: If we know the first term S1 = 3, the second term S2 = (3)(3) = 9.
The third term S3 = (3)(9) = 27
The fourth term S4 = (3)(27) = 81
(2) INSUFFICIENT: We can use this information to find the last term and previous terms, however, we don't know how many terms there are between the second to last term and the fourth term.
The correct answer is A
My thinking:
Say first term is 3
This is a Geometric Progression
3, 9, 27, 81, ........., 3**(n-1)
Ratio of 2nd to last term is 3**10
so (3**(n-1))/(3**2) = 3**10
that gives me n=11
The correct answer should be D