Is |x|<1?

[apoorva_srivastva]

Is |x|<1?

1.) |x+1| = 2 |x-1|
2.) |x-3| not equal to 3

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I would like to know that if there is mod sign on both the sides of the linear equation ....can we get rid of the mod and slove the equation as a normal linear equation as in statement 1

|x + 1| = 2|x - 1|

so by my logic can we get rid of the mod sign

(x+1) = 2(x-1)

and slove further.....

ALSO PLEASE SUGGEST ME ANY PREP MATERIAL FOR MODULUS AND INEQUALITIES

[StaceyKoprince]

The equation you offer is one possibility, but it is not the only possibility - the absolute value sign introduces multiple possible equations that all have to be checked (since this is a DS question).

You can find more material on general absolute values in the Number Properties book and on absolute value equations in the Equations, Inequalities and VICs book.