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gmat.tony.2009
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Inequalities Advanced Strategy

by gmat.tony.2009 Wed May 05, 2010 11:54 pm

Hi,

On page 191 (Guide 3, Fourth Edition) the explanation for question 11 says that since x < 0, 4/x < -1/3 evaluates to -12 < x. Can somebody explain the steps that were taken to reach the given answer?

Thanks.
parthatayi
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Re: Inequalities Advanced Strategy

by parthatayi Thu May 06, 2010 3:38 am

gmat.tony.2009 Wrote:Hi,

On page 191 (Guide 3, Fourth Edition) the explanation for question 11 says that since x < 0, 4/x < -1/3 evaluates to -12 < x. Can somebody explain the steps that were taken to reach the given answer?

Thanks.

4/x<-1/3
=4/x>1/3
=x<12
=x>-12
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Re: Inequalities Advanced Strategy

by gmat.tony.2009 Thu May 06, 2010 10:40 pm

parthatayi Wrote:
gmat.tony.2009 Wrote:Hi,

On page 191 (Guide 3, Fourth Edition) the explanation for question 11 says that since x < 0, 4/x < -1/3 evaluates to -12 < x. Can somebody explain the steps that were taken to reach the given answer?

Thanks.

4/x<-1/3
=4/x>1/3
=x<12
=x>-12


Thanks for your reply. But to solve this you assumed x to be +ve. Is this the correct approach? I am not doubting your approach...just need to clear it in my head.
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Re: Inequalities Advanced Strategy

by parthatayi Sat May 08, 2010 7:35 pm

Can you please post the complete question.
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Re: Inequalities Advanced Strategy

by gmat.tony.2009 Sun May 09, 2010 11:05 am

parthatayi Wrote:Can you please post the complete question.


If 4/x < -1/3, what are the possible range of values for x?
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Re: Inequalities Advanced Strategy

by parthatayi Sun May 09, 2010 2:47 pm

We need not worry abt the sign of x in this question.We shall treat x as positive.
We shall be careful if the question had included a modulus.
had it been 4/|x|,then we would have considered two conditions.
one is when x>0 and the another is x<0.
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Re: Inequalities Advanced Strategy

by adhirajkohli Mon May 10, 2010 7:33 am

parthatayi Wrote:We need not worry abt the sign of x in this question.We shall treat x as positive.
We shall be careful if the question had included a modulus.
had it been 4/|x|,then we would have considered two conditions.
one is when x>0 and the another is x<0.

I don't think so, because if you assume x = 2 then that would mean:
4/2 < -1/3
i.e. 2 < -1/3 which is incorrect.
It is mentioned in the question that x < 0.
Therefore,
4/x < -1/3
*** Multiplying both sides by 'x' which is Negitive. ***
When we multiply or divide an inequality by a negitive quantity the SIGN changes.
4 > - x/3
*** Multiplying both sides by 3 ***
12 > -x
*** Multiplying both sides by -1 ***
-12 < x
This is what the explanation in the guide says.
parthatayi
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Re: Inequalities Advanced Strategy

by parthatayi Mon May 10, 2010 11:00 pm

adhirajkohli Wrote:
parthatayi Wrote:We need not worry abt the sign of x in this question.We shall treat x as positive.
We shall be careful if the question had included a modulus.
had it been 4/|x|,then we would have considered two conditions.
one is when x>0 and the another is x<0.

I don't think so, because if you assume x = 2 then that would mean:
4/2 < -1/3
i.e. 2 < -1/3 which is incorrect.
It is mentioned in the question that x < 0.
Therefore,
4/x < -1/3
*** Multiplying both sides by 'x' which is Negitive. ***
When we multiply or divide an inequality by a negitive quantity the SIGN changes.
4 > - x/3
*** Multiplying both sides by 3 ***
12 > -x
*** Multiplying both sides by -1 ***
-12 < x
This is what the explanation in the guide says.


The main reason I have requested for the question is to check the condition on x.Please find the question in one of the posts above.It did not mention the condition for x.
gmat.tony.2009
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Re: Inequalities Advanced Strategy

by gmat.tony.2009 Tue May 11, 2010 9:39 pm

adhirajkohli Wrote:
parthatayi Wrote:We need not worry abt the sign of x in this question.We shall treat x as positive.
We shall be careful if the question had included a modulus.
had it been 4/|x|,then we would have considered two conditions.
one is when x>0 and the another is x<0.

I don't think so, because if you assume x = 2 then that would mean:
4/2 < -1/3
i.e. 2 < -1/3 which is incorrect.
It is mentioned in the question that x < 0.
Therefore,
4/x < -1/3
*** Multiplying both sides by 'x' which is Negitive. ***
When we multiply or divide an inequality by a negitive quantity the SIGN changes.
4 > - x/3

*** Multiplying both sides by 3 ***
12 > -x
*** Multiplying both sides by -1 ***
-12 < x
This is what the explanation in the guide says.


This makes sense. Thanks
tim
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Re: Inequalities Advanced Strategy

by tim Tue Jun 01, 2010 1:44 pm

adhirajkohli, that is totally correct. The initial explanation by parthatayi had several mistakes, so please ignore that explanation in its entirety..
Tim Sanders
Manhattan GMAT Instructor

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