by StaceyKoprince Thu May 28, 2009 2:12 pm
Nice! Yes, you can say that three consecutive multiples of 3 must contain four 3's as factors. Two of the three consecutive numbers will contain at least one multiple of 3. One of the three consecutive numbers must also be a multiple of 9 (which occurs every 3rd multiple of 3), so that number will contribute at least two 3's as factors.
I assume that the explanation doesn't point this out because we don't need that info to solve - but it would be nice if the explanation mentioned it anyway! :)
It's great that you noticed this extra info - because this might come into play on an even harder question!
Stacey Koprince
Instructor
Director, Content & Curriculum
ManhattanPrep