armandollaza Wrote:I chose E because k could be a 3 digit number, in which case 85, 86, 87, 88, 89 would satisfy the condition that the tens digit of k+5 is 4. Hence, either 3 or 8 could be k's tens digit. Did I miss something?
how's that? if k is 85, 86, 87, 88, or 89, then k + 5 is 90, 91, 92, 93, or 94, respectively. the tens digit of these numbers is 9, not 4.
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you are right, though, that k could be a three-digit number. this doesn't change anything, though, since all that's relevant to the problem is the last 2 digits of the number.
GENERAL FACT: if you want to know what happens to the last N digits of a number under multiplication, addition, or subtraction, then all you ever need to know is the last N digits.
division is the only operation under which any digit can ever be affected by the digits to its left.therefore, 140
< k
< 149, 240
< k
< 249, etc. will behave in EXACTLY the same way as 40
< k
< 49.
i should have written "LAST TWO DIGITS are 40
< k
< 49", with all the commentary also applying to the last 2 digits only.