If a<y<z<b; is ! y-a! < !y-b!
a. !z-a!<!z-b!
b. !y-a!<!z-b!
Ans : D
RonPurewal Wrote:the first thing you should do here is rephrase the question.
big takeaway:
if you see the ABSOLUTE VALUE OF A DIFFERENCE, you should recast it as the DISTANCE BETWEEN THE TWO THINGS on the number line.
therefore, |y - a| is the distance between y and a, and so on.
hence:
QUESTION: is y closer to a than to b ?
(1) z is closer to a than to b
(2) y is closer to a than z is to b
supratim7 Wrote:Going forward, If statement (2) were |y-a| = |z-b|, then also it would be sufficient. Am I right??
Regards | Supratim
supratim7 Wrote:Thank you :)
RonPurewal Wrote:the first thing you should do here is rephrase the question.
big takeaway:
if you see the ABSOLUTE VALUE OF A DIFFERENCE, you should recast it as the DISTANCE BETWEEN THE TWO THINGS on the number line.
therefore, |y - a| is the distance between y and a, and so on.
hence:
QUESTION: is y closer to a than to b ?
(1) z is closer to a than to b
(2) y is closer to a than z is to b
supratim7 Wrote:e.g.
If x is a positive number less than 10, is z greater than the average (arithmetic mean) of x and 10 ?
(1) On the number line, z is closer to 10 than it is to x.
(2) z = 5x
Can we decode Stmt (1) as
|10 - z| < |x - z|?