If a > b > 0, then √(a^2 - b^2) =

[ellie007]

If a > b > 0, then √(a^2 - b^2) =
a) a + b - √ 2ab
b) a - b + √ 2ab
c) √ [(a-b)^2 - 2ab)]
d) √(a + b) √(a - b)
e) (√a+√b) (√a-√b)

[ajithalexjacob]

If a > b > 0, then √(a^2 - b^2) =
a) a + b - √ 2ab
b) a - b + √ 2ab
c) √ [(a-b)^2 - 2ab)]
d) √(a + b) √(a - b)
e) (√a+√b) (√a-√b)

Unless, I have got it mixed up somewhere answer choice D looks the best.

√(a^2 - b^2) = √(a + b)(a - b) = √(a + b) x √(a - b)

Is this ok?

[tim]

cool; let us know if there are any further questions on this one..