Henry purchased 3 items during a sale

by **sachin.w** Tue Oct 16, 2012 9:22 am

I certainly missed the following takeaway:

IF YOU SEE A CRAZY QUESTION, TRY TO SIMPLIFY / REPHRASE / MANIPULATE IT

Thanks Ron!

by **tim** Tue Oct 16, 2012 3:23 pm

by **deepak1990verma** Sun Mar 22, 2015 9:45 am

Hello Ron,
Can this problem be solved using weighted average??
Our question is
is 0.20a+0.10(b+c) > 0.15 (a+b+c) ?
i.e 0.20a+0.10(b+c)/(a+b+c) >0.15.
i.e 20a+10(b+c)/(a+b+c) >15

a being the most expensive and c being the least.

Now using the number line method for statement I

10------------15------------20
(b+c)............................(a)

We know that cost of a is 50 and b+c would be at the max 40.
so the weighted average would be towards a. i.e always greater that 15.
Let me know if this approach is correct.

Thanks

by **RonPurewal** Wed Mar 25, 2015 1:51 am

yes, that does work... and it's absolutely ingenious (i'd never think to do that in a thousand years).

on the other hand, it does seem to ... belabor the problem quite a bit, as compared to the more "standard" ways of solving.

Henry purchased 3 items during a sale

Re: Henry purchased 3 items during a sale

Re: Henry purchased 3 items during a sale

Re: Henry purchased 3 items during a sale

Re: Henry purchased 3 items during a sale