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khwaja.shoaib
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GMAT Prep DS Question

by khwaja.shoaib Sun Nov 22, 2009 3:28 am

What is the remainder when the positive integer n is divided by the positive integer k, where k > 1


(1) n = (k+1)^3
(2) k = 5


OA = A

Can someone please explain this?
amitganguly2k12
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Re: GMAT Prep DS Question

by amitganguly2k12 Tue Nov 24, 2009 11:37 pm

Substitute k = 2,3,10.

Each time you will get 1 as remainder.So the OA.

thanks
pritesh.suvarna
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Re: GMAT Prep DS Question

by pritesh.suvarna Sun Nov 29, 2009 8:56 pm

(1) n = (k+1)^3 / k

Since the numerator is k+1 and denominator = k, the remainder will always be 1

A - Suff

(2) k = 5

n not defined.

Ans = A

Thanks
Pritesh
gayatri.ganpaa
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Re: GMAT Prep DS Question

by gayatri.ganpaa Mon Nov 30, 2009 12:50 am

Another way of solving this --
a) If you expand (k+1)^3 --> k^3+3k^2+3k+1 When you divide n/k- all the terms are divisible by k, except for 1. Therefore, remainder is 1.

b) does not give you any information about n
Ben Ku
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Re: GMAT Prep DS Question

by Ben Ku Thu Dec 24, 2009 6:54 pm

gayatri.ganpaa Wrote:Another way of solving this --
a) If you expand (k+1)^3 --> k^3+3k^2+3k+1 When you divide n/k- all the terms are divisible by k, except for 1. Therefore, remainder is 1.


This is a good algebraic proof for statement 1.

The plugging in numbers approach works; however, you cannot plug in and evaluate all values. I would suggest to look for the algebraic approach first.
Ben Ku
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