by atul.prasad Sat Nov 13, 2010 4:37 pm
It is given that
zy < xy < 0
consider zy < xy
If we could ascertain that y was > 0 , we could have divided both sides of inequality by y without changing the sign of inequality (note y cant be 0 here since it is given they are < 0)
Statement 1 tells us exactly that:
since z < x , and we have zy < xy y must be +ve
also since zy < 0 and xy < 0 , hence x and z must be negative.
So |x-z| + |x| = x - z + (-x) ( since x > z and |x| = -x because x < 0)
= -z = |z| since we evaluated above that z < 0
So 1 is sufficient
Statement 2 gives us exactly what we needed to know:
since y > 0, z < x and both x and z are -ve , as evaluated above.
So 2 is also sufficient
Hence D is the correct answer