Anonymous Wrote:What is the quickest way to solve this division problem:
10^8 - 10^2/ 10^7 - 10^3
wait, so this was a gmatprep problem? if so, where are the answer choices?
i'm going to assume that there are supposed to be parentheses around the first two terms, and also around the last two terms (so that the problem involves division of one binomial by another binomial). if not, then the problem has an incredibly ugly answer (and is not gmat-like at all).
you can factor out 10^2 from both top and bottom:
top = (10^2)(10^6 - 1)
bottom = (10^2)(10^5 - 10)
these cancel, leaving you with (10^6 - 1)/(10^5 - 10). (if you don't see how this is done, imagine x's in place of all the 10's.)
at that point, you may as well just evaluate the expression = 999,999 / 99,990 = 10,101 / 1010, which is as far as it reduces.
you
cannot, as the other poster says, just pull 1's out because they're smaller than other terms - unless the problem asks you to
approximate, in which case that's exactly what they want you to do.
in retrospect, this problem may be easiest by resorting to exact numbers asap: just evaluating the top and bottom right off the bat gives 999,999,900 / 9,999,000, after which knocking off 2 zeros gives what we have above (with less blood, sweat, and tears).
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if you happened to mis-transcribe the problem, and it was supposed to say (10^8 - 10^3) / (10^7 - 10^2), then the value of
that expression is exactly 10.