If you're experiencing a roadblock with one of the Manhattan Prep GMAT math strategy guides, help is here!
jigar24
Forum Guests
 
Posts: 64
Joined: Tue Mar 24, 2009 12:17 am
 

Geom Question bank query

by jigar24 Tue Jun 16, 2009 3:37 am

In the Geom question bank, for DS question

If angle BAD is a right angle, what is the length of side BD?
(1) AC is perpendicular to BD

(2) BC = CD

Solution says:
Using statements 1 and 2, we know that AC is the perpendicular bisector of BD. This means that triangle BAD is an isosceles triangle so side AB must have a length of 5 (the same length as side AD).

How can we say it’s an isosceles triangle? Is this a property? Please explain

Jigar
Pankaj.Dahiya
Students
 
Posts: 2
Joined: Fri Jun 19, 2009 7:32 am
Location: New Delhi, India
 

Re: Geom Question bank query

by Pankaj.Dahiya Sat Jun 20, 2009 11:15 am

Lets call AC=h and BC=CD=x
Using Pythagoras, AB=AD=x^2+h^2
j.vishal
Students
 
Posts: 4
Joined: Sun Jun 28, 2009 11:18 pm
 

Re: Geom Question bank query

by j.vishal Sat Jul 04, 2009 3:15 am

As AC bisects BD, it would bisect angle BAD as well. So angle BAC= angle CAD = 45. As the triangles ABC and CAD are also rightangle triangles, so angle CBA and angle CDA would be 45 each.

The side of the triangle facing the equal angles are also same so BC=CD=AB=AD. Hence Triangle BAD is an isosceles triangle.

Thanks
Ben Ku
ManhattanGMAT Staff
 
Posts: 817
Joined: Sat Nov 03, 2007 7:49 pm
 

Re: Geom Question bank query

by Ben Ku Fri Jul 31, 2009 1:51 am

Thanks j.vishal. That was a good explanation.

Another approach is to say that both right triangles ACB and ACD have two congruent legs, (AC = AC and CB = CD), then their hypotenuses are also congruent (AB = AD). BAD is isosceles.

Hope that helps!
Ben Ku
Instructor
ManhattanGMAT