* Can someone explain this Data Sufficiency question to me?

[aayushj]

A certain panel is to be composed of exactly three women and exactly two men, chosen from x women and y men. How many different panels can be formed with these constraints?

(1) If two more women were available for selection, exactly 56 different groups of three women could be selected.

(2) x = y + 1

~~~~~~~~~~~~~~
How do we go about figuring this out?

[bellthecatnow]

A certain panel is to be composed of exactly three women and exactly two men, chosen from x women and y men. How many different panels can be formed with these constraints?

(1) If two more women were available for selection, exactly 56 different groups of three women could be selected.

(2) x = y + 1

~~~~~~~~~~~~~~
How do we go about figuring this out?

From (1) -> we have to select 3 women from x+2 amd we can form 56 diff groups..

Using Combination formula :

(x+2)C3 = (x+2)(x+1)(x)/3 = 56
Solving for x here , you will get x = 6

But we still don't have Y from this equation . So Alone Insuffient .

(2) x= y+1

Alone insufficient.


Both taken together, Using x= 6 from 1), y = 5

The question can be solved with both equations together. My answer C)
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Can you post the Original answer please?

[Ben Ku]

Hi,

This folder is for questions from Manhattan GMAT's Strategy Guides and its accompanying materials. Please post where this problem was originally from. Thanks!