RonPurewal Wrote:as far as the theory underlying the question:
• with an "arithmetic progression",** the numbers are equally spaced. so, the average is the same as whatever number is in the middle.
• think about which number represents the average of the 4th and 12th terms.
• now, think about which number represents the average of the 1st through 15th terms.
that should be enough to get you started on discovering how this works (although, as pointed out above, you really don't have to-- you can just take all 4's).
Hi Ron, that's excellent thinking. However, I started with formulae: a+3d+a+11d = 8. so,
2a+14d = 8. so, S(15) = 15/2(
2a+14d) = 15/2*8 = 60.
but, only after reading ur answer I realized that every time I calculate the sum of an AP, I basically multiply the middle term with n.
Thanks.