I am wondering if somebody can help me understand the rationale behind the correct answer for this DS problem (located on pg 119 MGMAT Guide1 5th Ed.):
The number A is a two-digit positive integer; the number B is the two-digit positive integer formed by reversing the digits of A. If Q = 10B-A, what is the value of Q?
1) The tens digit of A is 7.
2) The tens digit of B is 6.
I am wondering:
1) Why B and "not A" is the answer.
2) What would be the answer if the equation was changed to Q = 10A-B.
Statement 1 indicates that 7 is located in the tens digit of A so in theory you can come up with a number from 70...79 that will allow you to know the value of B as per the requirement in the statement and in turn calculate the value of Q (I am seeing the equation as Q = (10*B) - A).
On the other hand I thought for statement 2 we know the value of B (60...69) but we would not be able to know the value of A (as the statement doesn't indicate that you can reverse the digits of B to determine the value of A). So in my mind I am thinking A as the answer.
BTW the official answer does make sense but I am wondering where am I going wrong.