by esledge Wed Dec 16, 2009 4:35 pm
The key to setting up the Double Set Matrix is that the two columns are opposite, mutually exclusive qualities (A and not-A). Same for the rows.
The trick here is recognizing that morning session is NOT the opposite of the afternoon session. Attending the morning session IS the opposite of not attending the morning session.
Here's what the matrix would look like for statement (2):
------------AM----not-AM------Total
PM---------unk------unk----(7/8)128 = 112
not-PM-----16-------0-------(1/8)128 = 16
Total-------unk------unk------128
By "unk" I mean the value is unknown--you could write alg expressions for these boxes, but wouldn't be able to solve. But you don't need to: We have the AM/not-PM box populated with the answer, which is 16.
If you solve this way, it's a good idea to circle the AM/not-PM box in the matrix before you start putting numbers in. I think C is a trap answer because (a) there are still so many unknowns in the chart when filled in for (2), and (b) the temptation to use the numbers you would already have put in a separate chart for (1).
I think you could use a Venn for this one. The Venn gets tricky when you have to consider the space OUTSIDE the circles. But in this problem, everyone attended one of the seminars or both, so everyone will be assigned to either the morning circle, the afternoon circle, or both.
Emily Sledge
Instructor
ManhattanGMAT