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sbosshard
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A certain jar contains only b black marbles...

by sbosshard Sun Nov 29, 2009 4:11 pm

A certain jar contains only b black marbles, w white marbles, and r red marbles. If one marble is to be chosen at random from the jar, is the probability that the marble chosen will be red greater than the probability that the marble chosen will be white?

(1) r/(b+w) > w/(b+r)
(2) b - w > r

Can you help me figure out where to start when approaching this problem (answer according to GMAT prep CAT test is A.

Thanks,
Stephan
cyber_office
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Re: A certain jar contains only b black marbles...

by cyber_office Wed Dec 02, 2009 7:08 pm

Hi,

My interpretation is as follows:

Since Statement 1 reads that r/(b+w) > w/(b+r), we can conclude that r/w must be > w/r since b is common to both denominators. It follows that r > w and hence r has a greater probability of being picked since there are more r marbles than w marbles.

Statement doesn't appear to provide much information: b - w > r. Alternatively, re-arranging, b - r > w. So it's a dead-end.

Not sure whether my logic is completely accurate, but the aforementioned approach is what I would have used on the test.

Regards.
bortheratyourside
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Re: A certain jar contains only b black marbles...

by bortheratyourside Thu Dec 03, 2009 4:49 am

now the probability of choosing r = r / ( b + w + r) ; the probability of choosing w is w / ( b + w+ r)...

Now S(1) tells us r/ (b+w) > w/ (b + r).. notice in the denominator, the numerator terms does not exist. it it did exist then we could solve the problem
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now S(1) can be re written as..
b+w/ r < b +r / w

add 1 to both sides
((b+w)/r )+ 1 < ((b +r)/ w)+ 1

b + w + r/r < b + w + r / w

invert the inequality
r/ ( b + w +r) > w / ( b + w+ r)

-----------------------------------------------------------------------------
ergo
s1 is good
RonPurewal
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Re: A certain jar contains only b black marbles...

by RonPurewal Sat Jan 09, 2010 3:50 am

look here:

a-certain-jar-contains-only-b-black-marbles-t881.html

12 posts, so your question is probably answered in there somewhere.