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abehrman
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75 = x^2 + y^2 + z^2

by abehrman Mon Jan 25, 2010 11:45 pm

75 can be written as the sum of the squares of 3 different positive integers. What is the sum of these 3 integers?

Is there a way that this can be done except by trial and error? Are there certain numbers that I should start with?
nishant_gourav
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Re: 75 = x^2 + y^2 + z^2

by nishant_gourav Tue Jan 26, 2010 3:03 pm

7,5,1
shilpman
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Re: 75 = x^2 + y^2 + z^2

by shilpman Thu Jan 28, 2010 5:05 pm

debasish.banerjee
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Re: 75 = x^2 + y^2 + z^2

by debasish.banerjee Wed Feb 03, 2010 3:02 pm

can someone pls. explain how 7,5,1 was chosen?
kevinmarmstrong
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Re: 75 = x^2 + y^2 + z^2

by kevinmarmstrong Fri Feb 05, 2010 5:24 pm

list the perfect squares less than 75:

1 4 9 16 25 36 49 64

Could the sum involve 64? The sum of the other two squares would have to be 11: impossible.

How about 49? The sum of the other two squares would have to be 26= 25 + 1

Thus 75= 7^2 + 5^2 +1^2
RonPurewal
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Re: 75 = x^2 + y^2 + z^2

by RonPurewal Thu Mar 04, 2010 10:40 am

Is there a way that this can be done except by trial and error?


unfortunately... not really.

takeaway:
do not expect a "textbook solution" for every problem.
if a problem has a SMALL NUMBER OF POSSIBILITIES, you can expect to have to try those possibilities, one by one.


Are there certain numbers that I should start with?


see here:
post7260.html#p7260