by Guest Sun May 20, 2007 8:59 am
Hi Vali -
5^21*4^11=2*10^n
First step - recognize that 4^11 = (2^2)^11 = 2^22 so:
5^21 * 2^22 =2*10^n
Second Step: note that 10 is equal to 5*2, so the left side of the equation gives you 21 factors of 10, with one 2 left over:
2*10^21 = 2*10^n, so you can see that n=21
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The solution above featured a shortcut, of actually combining prime exponents. A method that will always work is to reduce everything to prime exponents instead.
5^21 * 4^11 = 2*10^n
5^21 *(2^2)^11 = 2*5^n*2^n : Recognize that 4 = 2^2 and 10 = 2*5
5^21 * 2^22 = 2^(n+1) * 5^n
At this point, you can either the exponents of the 5 to see n=21, or the exponent of the 2's to see n+1=22, n=21.
Cheers,
Jeff