1001^2-999^2 / 101^2- 99^2

[marini.walker]

I got this in a practice exam sorry don't know how upload it to here.

I thought the answear was ten but I don't know how to prove it.

Whats the way to break this down:

(1001^2-999^2)/ (101^2- 99^2)

Marini

[parthatayi]

please use a^2-b^2=(a+b)(a-b)

(1001+999)(1001-999)/(101+99)(101-99)=10

[Ben Ku]

parthatayi provides an excellent solution.