2+2+(2^2)+(2^3)+(2^4)+(2^5)+(2^6)+(2^7)+(2^8) after the first two terms i.e (2^2)+(2^3)+(2^4)+(2^5)+(2^6)+(2^7)+(2^8) is a GP series with first term as 2^2 and ratio as 2. Using the formula for sum of GP series, for this part, the original equation becomes 2^2 + 2^2(1-2^7)/(1-2) = 2^2 + 2^2(127) = 2...

When N is divided by 10 the remainder is 1 and when N is divided by 3 the remainder is 2. What is the remainder when N is divided by 30?

1. 13
2. 3
3. 11
4. 6.
5. 17

Would like to know if there is any algebraic approach to such problems.

Any takers from the Instructor's team. ?? Any help will be greatly appreciated.