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by dghosh2602
Thu May 20, 2010 6:02 pm
 
Forum: Manhattan Prep GMAT Non-CAT Math
Topic: Guide 4 - Page 73 - Combinatorics Strategy
Replies: 1
Views: 1214
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Guide 4 - Page 73 - Combinatorics Strategy

G, M, P, J, B and C are supposed to sit in 6 different seats. But M and J won't sit together, how many different arrangements are possible? So, I know I can calculate the possibilities w/o constraints and subtract the possibilities with constraints and get the answer as 6! - 5! to get 480. What I am...
by dghosh2602
Fri May 21, 2010 2:42 pm
 
Forum: Manhattan Prep GMAT Non-CAT Math
Topic: Guide 4 - Page 73 - Combinatorics Strategy
Replies: 1
Views: 1472
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Guide 4 - Page 73 - Combinatorics Strategy

How can I solve Guide 4 - Page 73 - Combinatorics Strategy problem: Greg, Marcia, Peter, Jan, Bobby and Cindy go to a movie and sit next to each other in 6 adjacent seats. If Marcia and Jan will not sit next to each other, in how many arrangements can they sit? How can I solve this problem using the...
by dghosh2602
Sun May 23, 2010 11:40 pm
 
Forum: Manhattan Prep GMAT Non-CAT Math
Topic: Guide 4 - Probability - Chapter 12 - Page 191
Replies: 4
Views: 2688
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Guide 4 - Probability - Chapter 12 - Page 191

A gambler rolls three fair 6 sided dice. What is the probability that 2 of the dice show the same number but the third shows a different number? I don't see the flaw in my reasoning: Lets say the gambler played the dice the first time: 1/6 is the probability for any number to come up, then for the s...