Good effort Ilakshmir!!!. Perfect logic in the first two paragraphs of your explaination excepting the final solution though the final outcom is correct. Some would not hesitate to say you got 'lucky', but perhaps others might comment you made a 'compensating error' while yet some others would call ...

If p, q, r, and s are consecutive integers, with p < q < r < s and pq < rs;then r>0.5 and cannot be 0. In fact pr<qs making statement 1 sufficient.
Statement 2 give no information other than the universal truth 2>0.
The correct answer is indeed A.

Ilakshmir; "These are indeed the values I have derived in my solution" . They fact of the matter is that it isn't evident that the 'values' are derived since they can't be derived. Try the same problem if there are three families and one single to understand the error in your logic. You ge...

Ilakshmir; "how do you compute the number of ways just one family is seated together = 48?" Here it goes:- The number of ways that lucky family gets to sit together is 2*2=4 ways, and for each of those ways the unlucky family can be seperated by 1)both the family as well as single(2*2=4way...

jigar24
Perfect logical approach!!!. Will do for the two family problem but as the number of families increases and in particular odd numbers, matters may get cumbersome from the viewpoint of time.

This is quite intriguing!!!. A choice between the devil and the deep blue sea!!!;because all the given answers are incorrect. The closest of the choices to the correct answer is C. What is the source of the problem and please re-check the answer choices and revert and I shall be happy to explain thi...

Can an instructor help me resolve this confusion please. Thanks. I am very sorry!!!. The correct answer indeed is D. Please ignore my earlier post. Solution: The quickest mode is reverse gear, meaning consider that 7 games need to be played to decide the championship. The Probabilty of any one team...

Rajeev; "By applying this logic in this case, we are dealing with the problem as if all seven games were played with any possible outcomes of seven games (6-1, ,7,0, 5-2 etc) - That is when you get 128 in the denominator (2^7).". This is NOT true. notice the 20 possibilities(numerator) ell...

"Because you are interested in solving my problem" Yes!!!; that's pretty much the size of it. The probability of a 4-0 result is NOT 2/70 but is indeed {2*(1/2)^4} . I would recommend you write down all possibilities(sometimes known as the "brute force" method) and do a complete ...

"both x and y are positive"-NOT NECESSARY!!!

x=80 & y=-10 does satisfy both statements.

Ron;
Thanks indeed!
I was referring to the original transcription.

Hi, Total possible ways in which a passenger can ride 3 times is :er 3*3*3, since all choices are equally likely. Now, if we number the chairs 1,2,3 , then the passenger would have ridden on each of them if she/he chose it in the order 1,2,3 or 2,1,3 .. (essentially 3!) ways. So the probability sho...

Hi Atul Yes! indeed you are correct. You will notice that the passenger has doubled his chances by merely trying one more time i.e. Three attempts, prob=2/9 and 4 attempts, Prob=4/9. This is an interesting observation. Therefore, you may find it stimulating to find the minimum number of times the pa...

The original question and the manhattan solution is flawed. In mathematics, there is nothing as "approximate probability" Explaination: Possible outcomes: 1) The three points are equidistant from any other point by r units. 2) The three points are less than r units from any other point.(fa...

Shaji, Can you provide a more detailed explanation showing ur total outcomes and favorable outcomes? Please advise you need more explaination for the second or the third point?. Its the third that you need to focus your imagination. I shall be happy to clarify if you need . Can you explain how will...