JonathanSchneider Wrote:A separate approach:

Your first card could be anything. Since any card works, the probability of your first card working = 1.

Hi Can you explain why the probability of your first card working is 1 and not 1/12? Thanks

The following was a Q from my CAT exam. The red is my question within the explanation. Thank you. Q: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 Explanation given: 1) SUFFICIENT: Statement(1) tells us that x > 2^34, so we want to prove that 2^34 > 1010. We'll prove this by manipulating the ...

What is the minimum number of dollars you must pay me for answering your question? Zero, of course! :) The term "minimum" generally refers to a non-zero numerical value. Zero falls into that category, hence it is a possible answer. If "minimum" generally refers to a non-zero num...

Thank you. Your last sentence sums it up perfectly.

Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each. He handed out 2/3 of the chocolate bars and 3/5 of the toffee bars. How many packages of chocolates bars did Rasheed buy? (1) Rasheed bought 1 fewer packages of chocolate bars than toffe bars. (2) Ras...

Thanks.
Can you explain your equation from statement 1 more?

Ron,

Going back to the idea that the "which" should refer to the noun before it, do we refer to the "letters" as what is being referred to because "to Susan Huntington Dickinson" is a preposition and therefore can be ignored?

Thanks

Did not find this in a previous thread.

2+2+(2^2)+(2^3)+(2^4)+(2^5)+(2^6)+(2^7)+(2^8)

2^9

2^10

2^16

2^35

2^37

Is there a way to do this problem without calculating the powers of 2? Thanks.