Hi...could someone pls explain how to solve this one.. If zy < xy < 0, is mod (x-z) + mod (x) = mod (z) a) z < x b) y > 0 OA is D. This is a GMAT prep Q. Consider zy < xy < 0. Two possibilities arise: (1) z & x are positive and y is negative. OR (2) z & x are negative and ...

Is ABCD parallelogram ? 1) Opposite sides i.e. (AB, CD) and (BC, AD) are equal. 2) Opposite sides i.e. (AB, CD) and (BC, AD) are parallel. From (1): Consider any quadrilateral ABCD in which opposite sides are equal. This can only happen when these sides are parallel as well. Hence, ABCD is a parall...

if x > y^2 > Z^4, which of the following statements could be true? I. x > y > z II. z > y > x III. x > z > y a. I only b. I and II only c. I and III only d. II and III only e. I, II, and III OA: E we can know for sure that X has to be positive for it be to greater than Y^2 a...

A line parallel to PQ can never be equidistant from both P and Q. If you connect P and Q and draw a perpendicular bisector of PQ, ( a line that passes through the middle of PQ and is at right angles to PQ), this bisector will include ALL the possible points that are equidistant from both P and Q. T...

I think the very fact that the diagram in the Q has x-axis and y-axis passing through O makes it sufficient enough for us to conclude (or assume) that point O infact is that origin of the co-ordinate system. If x and y axes wouldn't have been mentioned in the diagram anywhere then it'd have been pos...

consider that travel time for 5 miles @30mph = t1 travel time for (x-5) miles @ 60mph= t2 and travel time if driven all along by 60 mph is = t3. Don would take more time by driving at variable speeds of 30 mph and 60mph than he'd take to drive at constant speed of 60mph. So, reqd % increase = [(t1+t...

I am assuming that you mean sqrt((0-s)^2 + (0 - t)^2) = 4 what do m1 and m2 represent?? And I still do not understand how you got t/s = 1. Can you please explain? putting values of m1 & m2 as mentioned by srinu84us into m1*m2=-1, you'll get t = s * (sqrt(3)) Put this back into t^2 + s^2 = 4 and...

Key points to note: (1) Applicant has been declined position. (2) Funding for summer jobs is limited. (3) Impossible to offer jobs to all those who want them (apply for the same). (4) (Govt office) forced to reject many highly qualified applicants. Now, consider options: (A) combining 2 & 3 abov...

Amir, I too am pondering on this since yesterday. I think your approach is correct but with a minor correction. P(med1 or med2) = P(med1) + P(med2) P(med1)= 1/14 P(med2) = P(not getting selected for 1st medicine) AND P(getting selected for 2nd med) P(not getting selected for 1st med) = 13/14 P(getti...

I did, thats the book answer. Thats why I am asking why the substitution method doesnt work You forgot to subract one set of (P+N+E). you have found values of P,N,E. What you now need is multiply EACH of the sides of these individual equations by 3 and ADD them together and solve for both sides : 3...

From 1:
(2^2 * 5^2)^x = 2^y * 5^z
==> 2^2x * 5^2x = 2^y * 5^z
==> 2x=y & 2x=z
==> y-z = 0.
So, (1) is sufficient.

From 2:
(2 * 5)^y = (2^2 * 5)^x * 5^z+1
==> 2^y * 5^y = 2^2x * 5^x+z+1
==> y=2x & y=x+z+1
This cannot be solved further. So, (2) is not sufficient.

Hence, (A).

Even if b cannot be zero, 'a' could still be zero. And hence, (a) CAN be Zero. That leaves with (e) as the correct option.

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Nimish.

X(X-1)>0 If product of two numbers is greater than zero, then either both of them are positive or both are negative (so not necessarily, X>0). Answer to your Question lies within. for (1), clearly this means X too is greater than 1 but less than X^2. So, Sufficient. for (2), Consider X= 0.1 (w...