1) (x+1)(|x|-1)>0 2) |x|<5 ANswer is (A). (x+1)(|x|-1)>0 - For this relation to hold true, X cannot be 0. X cannot be <0. X cannot be between 0 and 1. Therefore X is greater than 1. hence sufficient. |x|<5 - From this, -5 <x <5. So X may be or may not be greater than 1. Not suff...